These incllusions in a flame fusion synthetic ruby look so much similar to natural ruby inclusions i see in the lotus website inclusions.im really confused .how does one differentiate between synthetic and natural now.
synthetic rubies can look really similar to photos online.
Curved striae = lab
Straight striae = natural (in most cases)
gas bubbles or swirled, melted-looking inclusions in synthetics.
natural fingerprint inclusions, but they usually don’t have the same 3D, complex structure that real fingerprints in natural rubies do.
Natural rubies might also have tiny crystals of other minerals (like rutile or zircon) and those fine needle-like inclusions known as silk.
synthetic rubies have fewer impurities
rotate it in different light for the 3d effect
From my experience i think the best FINAL check is this:
spectroscopes digital one like this, i haven’t used it but thinking of getting one. (not sure if it is suitable for gemstones). If someone can advise, much appreciated.
thank you for your reply.will sure look into it.
Raja / Nirmala (@nirmalar32184) ,
Just reviewed the product datasheet for the HPCS330. Not sure the unit can be used “as is” for gemology.
Without an optical slit in front of the aperture window, the instrument may not be able to differentiate the light passing through a stone versus light passing around it. An optical slit will be necessary to filter out stray ambient light.
I know this post is over a month old, so if someone has purchased one of these instruments, they should attempt to add an optical slit before trusting the measured data.
Cheers!
-Troy
Thanks for the info, how to add the optical slit ?
Raja,
The illustration below shows a thin opaque black disk that would sit directly on the HPCS-330 sensor window with a small slit or hole in the center. The sample stone would have to be larger than the hole made into the disk. On top of the disk is a black opaque light shield using a known light source / torch.
This should block the stray light, but I am not sure how the reduction in light arriving at the sensor will affect the measurement.
Let me know if this makes sense or not. I can try to redraw the diagram with better detail if needed.
Cheers!
-Troy